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remove link.go block on oldIntf if we already have a connection to the same node, this spams connections, so it's not a good long-term fix if that's where the goroutine leak is
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parent
df1239b054
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1daf3e7bd7
@ -252,16 +252,12 @@ func (intf *link) handler() error {
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intf.info.box = meta.box
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intf.info.box = meta.box
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intf.info.sig = meta.sig
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intf.info.sig = meta.sig
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intf.links.mutex.Lock()
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intf.links.mutex.Lock()
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if oldIntf, isIn := intf.links.links[intf.info]; isIn {
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if _, isIn := intf.links.links[intf.info]; isIn {
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intf.links.mutex.Unlock()
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intf.links.mutex.Unlock()
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// FIXME we should really return an error and let the caller block instead
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// FIXME we should really return an error and let the caller block instead
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// That lets them do things like close connections on its own, avoid printing a connection message in the first place, etc.
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// That lets them do things like close connections on its own, avoid printing a connection message in the first place, etc.
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intf.links.core.log.Debugln("DEBUG: found existing interface for", intf.name)
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intf.links.core.log.Debugln("DEBUG: found existing interface for", intf.name)
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intf.msgIO.close()
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intf.msgIO.close()
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if !intf.incoming {
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// Block outgoing connection attempts until the existing connection closes
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<-oldIntf.closed
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}
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return nil
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return nil
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} else {
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} else {
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intf.closed = make(chan struct{})
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intf.closed = make(chan struct{})
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